A function $f$ is continuous on a point ${x}_{0}$ if

For all $\epsilon >0$, there exists a $\phantom{\rule{thickmathspace}{0ex}}\delta >0$,
such that $\mid x-{x}_{0}\mid <\delta $ implies $\mid f(x)-f({x}_{0})\mid <\epsilon $.

Given a concret function (who is continuous), a ${x}_{0}$
and a $\epsilon >0$, you have to find a $\delta >0$
which verifies the above condition. And you will be noted according to
this $\phantom{\rule{thickmathspace}{0ex}}\delta $: more it is close to the best possible value, better
will be your note.
Other exercises on:

The most recent versionPlease take note that WIMS pages are interactively generated; they are not ordinary HTML files. They must be used interactively ONLINE. It is useless for you to gather them through a robot program.

- Description: on the definition of continuity: given epsilon, find delta. serveur web interactif avec des cours en ligne, des exercices interactifs, des calculatrices et traceurs en ligne
- Keywords: serveur interactif, enseignement, cours en ligne, ressources pédagogiques, sciences, langues, qcm,classes,exercices, analysis, epsilon, delta, continuity, limit, calculus